Consider the following code:
string propertyName;
var dateList = new List<DateTime>() { DateTime.Now };
propertyName = dateList.GetPropertyName(dateTimeObject => dateTimeObject.Hour);
// I want the propertyName variable to now contain the string "Hour"
Here is the extension method:
public static string GetPropertyName<T>(this IList<T> list, Func<T, object> func) {
//TODO: would like to dynamically determine which
// property is being used in the func function/lambda
}
Is there a way to do this? I thought that maybe this other method, using Expression<Func<T, object>> instead of Func<T, object> would give me more power to find what I need, but I am at a loss at how.
public static string GetPropertyName<T>(this IList<T> list, Expression<Func<T, object>> expr) {
// interrogate expr to get what I want, if possible
}
This is the first time I have done anything this deep with Linq, so maybe I am missing something obvious. Basically I like the idea of passing in lambdas, so that I get compile-time checking, but I don't know that my idea on how I can use them in this particular case will work.
Thanks
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Something like this should do the trick:
public static string GetPropertyName<T>(this IList<T> list, Expression<Func<T, object>> expr) { MemberExpression member_expression = expr.Body as MemberExpression; if (member_expression == null) throw new ArgumentNullException("member_expression"); MemberInfo member = member_expression.Member; PropertyInfo property = member as PropertyInfo; string proname = memeber.name; }WARNING: Air Code!
Jason Bunting : Thanks for answering Nathan, I appreciate it. You were close enough, and since you said "something like this should do the trick," you were not technically wrong! I will accept @gcores' answer because his was correct without me having to make changes. I still gave you a +1 for answering though!sighohwell : Theres a minor difference between Nathan's and gcores's answers with regard to some fringe cases such as nullable decimals (if I remember correctly!). For those properties the body of the expression isn't a MemberExpression but a UnaryExpression (dealt with in gcores's answer).Nathan W : @Jason Thats cool, I would have accepted his answer as well as it is more complete then mine.Jason Bunting : @sighohwell: I know, that is why I accepted @gcores' answer and felt that @Nathan's was good enough to deserve some credit, since it would have helped point me in the right direction if @gcores hadn't posted. -
This is the version I use, it returns a PropertyInfo, but getting the name is trivial.
public static PropertyInfo GetProperty<T>(Expression<Func<T, object>> expression) { MemberExpression memberExpression = null; if (expression.Body.NodeType == ExpressionType.Convert) { memberExpression = ((UnaryExpression) expression.Body).Operand as MemberExpression; } else if (expression.Body.NodeType == ExpressionType.MemberAccess) { memberExpression = expression.Body as MemberExpression; } if (memberExpression == null) { throw new ArgumentException("Not a member access", "expression"); } return memberExpression.Member as PropertyInfo; }Jason Bunting : Awesome, this was perfect. Now my hack is complete! :P Ah, I hate having to come up with these workarounds to get stuff to work "like it should." I mean, it's fun and all, but just too painful when there is real work to do. Thank you! -
Hi,
here is a very easy and fast way to do it on this blog: http://blog.bittercoder.com/PermaLink,guid,206e64d1-29ae-4362-874b-83f5b103727f.aspx
So given:
Func func = Name => "Value";
You can get the lambda parameter "Name" from the function delegate by calling:
func.Method.GetParameters()[0].Name (would return "Name")
Here's the revised Hash method from Andrey:
public Dictionary<string, T> Hash<T>(params Func<string, T>[] args) where T : class { var items = new Dictionary<string, T>(); foreach (var func in args) { var item = func(null); items.Add(func.Method.GetParameters()[0].Name, item); } return items; }Hope it helps, Patrick
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Just a side note: func.Method.GetParameters()[0].Name is extremelly fast when compared with compiling the lambda and extracting the member expression, then the member info, then the name.
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