Hi,
can you increment a hex value in Java? i.e. "hex value" = "hex value"++
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What do you mean with "hex value"? In what data type is your value stored?
Note that int/short/char/... don't care how your value is represented initially:
int i1 = 0x10; int i2 = 16;i1andi2will have the exact same content. Java (and most other languages as well) don't care about the notation of your constants/values. -
Yes. All ints are binary anyway, so it doesn't matter how you declare them.
int hex = 0xff; hex++; // hex is now 0x100, or 256 int hex2 = 255; hex2++; // hex2 is now 256, or 0x100 -
It depends how the hex value is stored. If you've got the hex value in a string, convert it to an Integer, increment and convert it back.
int value = Integer.parseInt(hex, 16); value++; String incHex = Integer.toHexString(value); -
Short answer: yes. It's
myHexValue++;Longer answer: It's likely your 'hex value' is stored as an integer. The business of converting it into a hexadecimal (as opposed to the usual decimal) string is done with
Integer.toHexString( myHexValue )and from a hex string with
Integer.parseInt( someHexString, 16 );M.
Michael Myers : Or String.format("%x", myHexValue); -
The base of the number is purely a UI issue. Internally an integer is stored as binary. Only when you convert it to human representation do you choose a numeric base. So you're question really boils down to "how to increment an integer?".
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